Solve by Cramer's rule: 2x+y+z=1 x-y+2z=-1 3x+2y-z=4

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Q. Solve by Cramer's rule:
2x+y+z=1
x-y+2z=-1
3x+2y-z=4

Solution:
 

  Since the delta value is non zero, so the solution exists.









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